Seismosoft | Earthquake Engineering Solutions

In example 11, a lumped mass of 0.49 kip-sec2/in is applied in the X-direction. How it was calculated? I tried but my answer does not match. Please help.

In example 5 – Partial fixity end release, the value of Mass/length = 0.00024288 [kip×sec2/in2] is given. However, my calculation = (0.15x540/123x386.2205) = 0.00012136 [kip×sec2/in2]. Please explain.

Hi, I'm a new user. How the value of GJ in Element Class for elfrm element is being calculated for a rectangular section (e.g. 1.2mx0.2m)?