Hello
I have a problem with my seismostruct file.
I have to calculate eigenvalues and I have done the exemple given in the manual. It worked perfectly. I have extended it to a 16 columns / 10 storeys building and I have the error shown in the subject title.
My file can be found here : http://ovh.to/nCcm3DW
For the periods that seismocstruct has given, they are very different from what I have been able to find by hand calculations.
Is it possible to check the stiffness / mass matrices given by the software? I have assumed a stiffness k=12EI/L^3 per column so multiplied by 16 for 1 storey. It seem to be less stiff in the software calculation.
Thanks
Nicolas
Could not re-orthogonalise all Lanczos vectors
Re: Could not re-orthogonalise all Lanczos vectors
Dear Nico1978,
Could you please check your file? In the uploaded file it seems that you have not assigned reinforcement to the column sections.
Could you please check your file? In the uploaded file it seems that you have not assigned reinforcement to the column sections.
Zoi Gronti
Seismosoft Srl.
Seismosoft Srl.
Re: Could not re-orthogonalise all Lanczos vectors
Regarding the lower than theoretical stiffness - this is to be expected. The equation for column stiffness - 12EI/L^3 - is valid only for infinitely rigid beams. If you desired to do so, you could emulate such a condition by placing rotational restraints at all nodes which constitute a beam-column connection. This would effectively be equivalent to infinitely rigid beams. Alternatively, you could assign outrageously high E and I values to the beams, but this could create some numerical instabilities.
Tim Huff
Re: Could not re-orthogonalise all Lanczos vectors
Thank you huffte for your answer. I will try to place a rotaional restraint at all nodes.
Dear z.gronti.
This was intentional to not assign any reinforcement into column section. I have to do an assignement where no reinforcement are given and I wanted to be as close as possible to the problem. Does the fact that not placing any reinforcment bar can create an instability for the result?
Thanks
Nicolas
Dear z.gronti.
This was intentional to not assign any reinforcement into column section. I have to do an assignement where no reinforcement are given and I wanted to be as close as possible to the problem. Does the fact that not placing any reinforcment bar can create an instability for the result?
Thanks
Nicolas
Re: Could not re-orthogonalise all Lanczos vectors
Dear Nico1978,
I don't think that if you don't assign reinforcement can cause instability to the eigenvalue analysis results. Please select the Jacobi with Ritz transformations eigen-solver in the Eigenvalue tab of the Tools > Project Settings to complete the eigenvalue analysis.
I don't think that if you don't assign reinforcement can cause instability to the eigenvalue analysis results. Please select the Jacobi with Ritz transformations eigen-solver in the Eigenvalue tab of the Tools > Project Settings to complete the eigenvalue analysis.
Zoi Gronti
Seismosoft Srl.
Seismosoft Srl.
Re: Could not re-orthogonalise all Lanczos vectors
Dear z.gronti
Thanks a lot. It's working well.
Huffte
Thanks to you also. I have obtained the same results than the ones obtained by hand calculation when I restrained all nodes in rotation.
Regards
Nicolas
Thanks a lot. It's working well.
Huffte
Thanks to you also. I have obtained the same results than the ones obtained by hand calculation when I restrained all nodes in rotation.
Regards
Nicolas
Re: Could not re-orthogonalise all Lanczos vectors
Good to hear Nico1978. It's a good way to verify software since the calculation is amenable by had with the restraints. Realize, however, that for modeling actual structures, you should likely delete the rotational restraints before proceeding with the analyses.
Tim Huff